А 1)√a+1/(√a+2)=(a+2√a+1)/(√a+2)=(√a+1)²/(√a+2) 2)√a+1/(√a-2)=(a-2√a+1)/(√a-2)=(√a-1)²/(√a-2)3 (√a+1)²/(√a+2) *(√a-1)²/(√a-2) *(√a-2)(√a+2)=(a-1)² Получили √(a-1)²=|a-1|=|0,8-1|=|-0,2|=0,2 b 1)(√a+1)(a-√a+1)/(√a+1) -√a=a-√a+1-√a=a-2√a+1=(√a-1)² 2)√(√a-1)²+√a=|√a-1|-√a=|√0,8-1|+√0,8=1-√0,8+√0,8=1
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А1)√a+1/(√a+2)=(a+2√a+1)/(√a+2)=(√a+1)²/(√a+2)
2)√a+1/(√a-2)=(a-2√a+1)/(√a-2)=(√a-1)²/(√a-2)3
(√a+1)²/(√a+2) *(√a-1)²/(√a-2) *(√a-2)(√a+2)=(a-1)²
Получили
√(a-1)²=|a-1|=|0,8-1|=|-0,2|=0,2
b
1)(√a+1)(a-√a+1)/(√a+1) -√a=a-√a+1-√a=a-2√a+1=(√a-1)²
2)√(√a-1)²+√a=|√a-1|-√a=|√0,8-1|+√0,8=1-√0,8+√0,8=1