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Skodavod
@Skodavod
July 2022
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Первое уравнение уравнять, второе дописать, после написать полное ионное и сокращенное.
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svetka1574
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2СH3COOH + Mg -> (CH3COO)2Mg + H2
2CH3COO(-) + 2H(+) + Mg(0) -> 2CH3COO(-) + Mg(+2) + H2(0)
2H(+)+ Mg(0) -> Mg(+2) + H2(0)
2HCOOH + Ba(OH)2 -> (HCOO)2Ba + 2H2O
2HCOO(-) + 2H(+) + Ba(+2) + 2OH(-) -> 2HCOO(-) + Ba(+2) + 2H2O
2H(+) + 2OH(-) -> 2H2O
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Answers & Comments
Verified answer
2СH3COOH + Mg -> (CH3COO)2Mg + H22CH3COO(-) + 2H(+) + Mg(0) -> 2CH3COO(-) + Mg(+2) + H2(0)
2H(+)+ Mg(0) -> Mg(+2) + H2(0)
2HCOOH + Ba(OH)2 -> (HCOO)2Ba + 2H2O
2HCOO(-) + 2H(+) + Ba(+2) + 2OH(-) -> 2HCOO(-) + Ba(+2) + 2H2O
2H(+) + 2OH(-) -> 2H2O