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oks63
@oks63
April 2021
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Первое уравнения . Пожалуйста!!!
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380937397523
Sin3x=sin5x
sin3x-sin5x=0
\\sinA-sinB=2*sin((A-B)/2)*cos((A+B)/2)\\
2*sin(-x)*cos4x=0
-2*sinx*cos4x=0 <=>
либо sinx=0 либо cos4x=0 =>
=> x=
n, n є Z либо x=
/2+
n, n є Z.
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Answers & Comments
sin3x-sin5x=0
\\sinA-sinB=2*sin((A-B)/2)*cos((A+B)/2)\\
2*sin(-x)*cos4x=0
-2*sinx*cos4x=0 <=>
либо sinx=0 либо cos4x=0 =>
=> x=n, n є Z либо x=/2+n, n є Z.