Первое задание. Помогите аж. Created by Andrejvich. algebra-ru

Первое задание. Помогите аж...

dmdm15 А)(√x + 2√3) / (x - 12) = (√x + √12) / (√x + 12)(√x - 12) = 1 / (√x - 12)
б)(√7a + √14b) / (a + 2√2ab + 2b) = √7(a + 2b) / (√a + √2b)^2 = √7 / (√a + 2b)

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GreatFilter $\frac{ \sqrt{x} +2 \sqrt{3} }{x-12} = \frac{ \sqrt{x} + \sqrt{12} }{x-12} = \frac{ \sqrt{x} + \sqrt{12} }{(\sqrt{x} - \sqrt{12})(\sqrt{x} + \sqrt{12})} = \frac{1}{\sqrt{x} - \sqrt{12} }$
$\frac{ \sqrt{7a}- \sqrt{14b} }{a+2 \sqrt{2ab} +2b} = \frac{ \sqrt{7}* \sqrt{a} - \sqrt{7}*\sqrt{2b} }{a+ \sqrt{8ab} +2b} = \frac{ \sqrt{7a} ( \sqrt{a} - \sqrt{2b)} }{( \sqrt{a}+ \sqrt{2b} )^{2} } = \frac{ \sqrt{7a} }{\sqrt{a}+ \sqrt{2b} } =$

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