Первый член геометрической прогрессии равен 3, знаменатель равен 3. Найдите сумму пяти первых членов этой прогрессии.
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Verified answer
B1 = 3q = 3
S5 - ?
S5 = (b1*(q^n - 1))/(q - 1) = (3*(3^5-1))/(3-1) = 363
Verified answer
В5=в1*q^4=3*3^4=243 S5=(B5*q-B1)\(q-1)=(243*3-3)\(3-1)=726\2=363