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DiamondDiva1
@DiamondDiva1
August 2022
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DariosI
Verified answer
1)
f(x)=
ОДЗ:
x²-3x+2=0
D=9-4*2=1
x₁=(3-1)/2=1
x₂=(3+1)/2=2
x∈(-∞; 1)∨(1; 2)∨(2; +∞)
2) f(x)=
OДЗ:
x²-1≥0
(x+1)(x-1)≥0
x∈(-∞-1]∨[1; +∞)
3-x>0
x<3
x∈(-∞; 3)
Объединим области определения
x∈(-∞; -1]
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Answers & Comments
Verified answer
1)f(x)=
ОДЗ:
x²-3x+2=0
D=9-4*2=1
x₁=(3-1)/2=1
x₂=(3+1)/2=2
x∈(-∞; 1)∨(1; 2)∨(2; +∞)
2) f(x)=
OДЗ:
x²-1≥0
(x+1)(x-1)≥0
x∈(-∞-1]∨[1; +∞)
3-x>0
x<3
x∈(-∞; 3)
Объединим области определения
x∈(-∞; -1]