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Rufina7
@Rufina7
August 2022
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<p>(5+2y)(y-3)-2(y-1)^2=0 Решить уравнение</p>
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Kixcertborn2
Verified answer
(5+2y)(y-3)-2(y-1)^2=0
5у-15+2у^2-6у-2(y^2-2y+1)=0
5y-15+2y^2-6y-2y^2+4y-2=0
3y-17=0
3y=17
y=17/3=5 2/3
Ответ: 5 2/3
1 votes
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Answers & Comments
Verified answer
(5+2y)(y-3)-2(y-1)^2=05у-15+2у^2-6у-2(y^2-2y+1)=0
5y-15+2y^2-6y-2y^2+4y-2=0
3y-17=0
3y=17
y=17/3=5 2/3
Ответ: 5 2/3