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Twilighte007
@Twilighte007
August 2022
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Please, хотя бы try to решить это задание
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sedinalana
Verified answer
X(y-7)/y(y-7)=x/y
(10a-15b)/16a-24b)=5(2a-3b)/8(2a-3b)=5/8
(2m+14)/(m²-49)=2(m+7)/(m-7)(m+7)=2/(m-7)
(p²-25q²)/(2p-10q)=(p-5q)(p+5q)/2(p-5q)=(p+5q)/2
(x²-4x+4)/(x²-2x)=(x-2)²/x(x-2)=(x-2)/x
(3y²+24y)/(y²+16y+64)=3y(y+8)/(y+8)²=3y/(y+8)
(a²+a+1)/(a³-1)=(a²+a+1)/(a-1)(a²+a+1)=1/(a-1)
(b+2)/(b³+8)=(b+2)/(b+2)(b²-2b+4)=1/(b²-2b+4)
0 votes
Thanks 2
amin07am
4) 5 забыли.
amin07am
5) тоже х (х-2)
MrCalling
Verified answer
Решение во вложении.
1 votes
Thanks 1
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Answers & Comments
Verified answer
X(y-7)/y(y-7)=x/y(10a-15b)/16a-24b)=5(2a-3b)/8(2a-3b)=5/8
(2m+14)/(m²-49)=2(m+7)/(m-7)(m+7)=2/(m-7)
(p²-25q²)/(2p-10q)=(p-5q)(p+5q)/2(p-5q)=(p+5q)/2
(x²-4x+4)/(x²-2x)=(x-2)²/x(x-2)=(x-2)/x
(3y²+24y)/(y²+16y+64)=3y(y+8)/(y+8)²=3y/(y+8)
(a²+a+1)/(a³-1)=(a²+a+1)/(a-1)(a²+a+1)=1/(a-1)
(b+2)/(b³+8)=(b+2)/(b+2)(b²-2b+4)=1/(b²-2b+4)
Verified answer
Решение во вложении.