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irodacrasavica
@irodacrasavica
May 2021
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плииииз 18-25 пожалуйста
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sangers1959
Verified answer
18. 2x²-IxI-1≥0
2x²-x-1≥0 D=9
x₁=1 x₂=-0,5
(x-1)(x+0,5)≥0
-∞_____+____-0,5____-_____1______+_____+∞
x₁∈(-∞;-0,5]∨[1;+∞).
2x+x-1≥0 D=9
x₁=-1 x₂=0,5
(x+1)(x-0,5)≥0
-∞_____+____-1_____-____0,5_____+____+∞
x₂∈(-∞;-1]∨[0,5;+∞) ⇒
x∈(-∞;1]∨[1;+∞).
Ответ: В)
1 votes
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Verified answer
18. 2x²-IxI-1≥02x²-x-1≥0 D=9
x₁=1 x₂=-0,5
(x-1)(x+0,5)≥0
-∞_____+____-0,5____-_____1______+_____+∞
x₁∈(-∞;-0,5]∨[1;+∞).
2x+x-1≥0 D=9
x₁=-1 x₂=0,5
(x+1)(x-0,5)≥0
-∞_____+____-1_____-____0,5_____+____+∞
x₂∈(-∞;-1]∨[0,5;+∞) ⇒
x∈(-∞;1]∨[1;+∞).
Ответ: В)