Ответ:
Объяснение:
1)
IACI²=17²-8²=289-64=225
IACI=15
sinα=8/17
cosα=IACI/17=15/17
tgα=8/IACI=8/15
sinβ=IACI/17=15/17
cosβ=8/17
tgβ=IACI/8=15/8
2)
IABI²=21²+20²=441-400=841
IABI=29
sinα=21/IABI=21/29
cosα=20/IABI=20/19
tgα=21/20
sinβ=20/IABI=20/29
cosβ=21/IABI=21/29
tgβ=20/21
3)
IABI²=1²+2²=1+4=5
IAB=√5
sinα=1/IABI=1/√5=√5/5
cosα=2/IABI=2/V5=2V5/5
tgα=1/2
sinβ=2/AB=2/√5=2√5/5
cosβ=1/AB=1/√5=√5/5
tgβ=2/1=2
4)
IBCI²=25²-24²=265-576=49
IBCI=7
sinα=IBCI/25=7/25
cosα=24/25
tgα=IBCI/24=7/24
sinβ=24/25
cosβ=IBCI/25=7/25
tgβ=24/IBCI=24/7
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Answers & Comments
Ответ:
Объяснение:
1)
IACI²=17²-8²=289-64=225
IACI=15
sinα=8/17
cosα=IACI/17=15/17
tgα=8/IACI=8/15
sinβ=IACI/17=15/17
cosβ=8/17
tgβ=IACI/8=15/8
2)
IABI²=21²+20²=441-400=841
IABI=29
sinα=21/IABI=21/29
cosα=20/IABI=20/19
tgα=21/20
sinβ=20/IABI=20/29
cosβ=21/IABI=21/29
tgβ=20/21
3)
IABI²=1²+2²=1+4=5
IAB=√5
sinα=1/IABI=1/√5=√5/5
cosα=2/IABI=2/V5=2V5/5
tgα=1/2
sinβ=2/AB=2/√5=2√5/5
cosβ=1/AB=1/√5=√5/5
tgβ=2/1=2
4)
IBCI²=25²-24²=265-576=49
IBCI=7
sinα=IBCI/25=7/25
cosα=24/25
tgα=IBCI/24=7/24
sinβ=24/25
cosβ=IBCI/25=7/25
tgβ=24/IBCI=24/7