Плиз помогите СРОЧНО Дам 45 балов Заранее огромное спасибо. Created by daryavtyurina06. algebra-ru

Плиз помогите СРОЧНО Дам 45 балов Заранее огромное спасибо...

daryavtyurina06 @daryavtyurina06

July 2021 1 25 Report

Плиз помогите
СРОЧНО
Дам 45 балов
Заранее огромное спасибо

Answers & Comments

tshnyryova2000

Вариант 1.

$\frac{a {}^{8}b {}^{5} c {}^{20}}{a {}^{10}b {}^{4} c {}^{3} } = a {}^{ - 2} bc {}^{17 } = \frac{bc {}^{17} }{a {}^{2} }$

$\frac{3a + 3b}{4a + 4b} = \frac{3(a + b)}{4(a + b)} = \frac{3}{4} = 0.75$

$\frac{a {}^{2} - 9 }{3a + 9} = \frac{(a - 3)(a + 3)}{3(a + 3)} = \frac{a - 3}{3}$

$\frac{(a + 2) {}^{2} }{7a {}^{2} + 14a } = \frac{(a + 2) {}^{2}}{7a(a + 2)} = \frac{a + 2}{7a}$

$\frac{y {}^{2} - 16 }{4y {}^{2} - y {}^{3} } = \frac{(y - 4)(y + 4)}{ - y {}^{2} ( - 4 + y)} = - \frac{y + 4}{y {}^{2} }$

$\frac{(a + 1) {}^{2} + (a - 1) {}^{2} }{3(a {}^{2} + 1) } = \\ \frac{a {}^{2} + 2a + 1 + a {}^{2} - 2a + 1 }{3(a {}^{2} + 1) } = \\ \frac{2(a {}^{2} + 1)}{3(a {}^{2} + 1) } = \frac{2}{3}$

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