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irinkka96
@irinkka96
June 2022
1
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По формуле корней решите квадратное уравнение
1) x^2+6x+8=0
2) x^2+4x+2=0
3)3x^2-6x-2=0
4) 3x^2+6x-2=0
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sapnad
1) По теореме виета
х1+х2=-6
х1*х2=8
х1=-2
х2=-4
2)D=4^2-4*1*2=16-8=8
х1=(4-√8)/2*2
х2=
(4+√8)/2*2
3)D=(-6)^2 - 4*3*(-2)= 36+24=60
х1=
(6-√60)/2*3
х2=
(6+√60)/2*3
4)D=6^2-4*3*(-2)+36+24=60
х1=(-6-√60)/2*3
х2=(-6+√60)/2*3
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Answers & Comments
х1+х2=-6
х1*х2=8
х1=-2
х2=-4
2)D=4^2-4*1*2=16-8=8
х1=(4-√8)/2*2
х2=(4+√8)/2*2
3)D=(-6)^2 - 4*3*(-2)= 36+24=60
х1=(6-√60)/2*3
х2=(6+√60)/2*3
4)D=6^2-4*3*(-2)+36+24=60
х1=(-6-√60)/2*3
х2=(-6+√60)/2*3