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thenastyaan
@thenastyaan
August 2022
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по теореме Пифагора
найти х
дано: ABCD - трапеция; AD = 9
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alinka7777777
Х²=6²-4² AE=9-5=4см
х²=36-16
х²=20
х=√5*4
х=2√5
6 votes
Thanks 4
Spasaev
AB = CD => трапеция равнобедренная => AD = BC + 2AE
AE = (AD - BC) / 2 = (9 - 5) / 2 = 2 cм
Т.к. ∠E = 90°, то по теореме Пифагора AB² = AE² + BE²
Отсюда BE = √AB²-AE² = √36-4 = √32 = 4√2 см
4 votes
Thanks 6
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Answers & Comments
х²=36-16
х²=20
х=√5*4
х=2√5
AE = (AD - BC) / 2 = (9 - 5) / 2 = 2 cм
Т.к. ∠E = 90°, то по теореме Пифагора AB² = AE² + BE²
Отсюда BE = √AB²-AE² = √36-4 = √32 = 4√2 см