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vavavvavavavava
@vavavvavavavava
July 2022
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по т.Виета
х^2-3х-5-√7=0
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mmb1
Verified answer
Теорема Виета для уравнения
x^2 + px + q =0
x1 + x2 = -p
x1*x2=q
x1+x2=3
x1*x2 = -5 - √7
(тут тяжело в уме посчитать, поэтому решим через дискриминант а потом поставим сюдя
D= 9+ 4(5 + √7) = 9 + 20 + 4√7 = 29 + 4√7 = 28 + 2*2√7*1 + 1 = (2√7)² + 2*2√7 + 1² = (2√7 +1)²
√D = 2√7 + 1
x12= (3+-(2√7+1)/2
x1= 2 + √7
x2 = 1 - √7
3 votes
Thanks 2
vavavvavavavava
спасибо большое))
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Answers & Comments
Verified answer
Теорема Виета для уравненияx^2 + px + q =0
x1 + x2 = -p
x1*x2=q
x1+x2=3
x1*x2 = -5 - √7
(тут тяжело в уме посчитать, поэтому решим через дискриминант а потом поставим сюдя
D= 9+ 4(5 + √7) = 9 + 20 + 4√7 = 29 + 4√7 = 28 + 2*2√7*1 + 1 = (2√7)² + 2*2√7 + 1² = (2√7 +1)²
√D = 2√7 + 1
x12= (3+-(2√7+1)/2
x1= 2 + √7
x2 = 1 - √7