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Danya20040804
@Danya20040804
November 2021
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под действием какой силы совершается работа 200 кДж на пути 0.8 км?
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fatt52
Verified answer
A=2*10^5 Дж s=800 м F=?
===
A=F*s
F=A/s=2*10^5/800=250 H
========================
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Answers & Comments
Verified answer
A=2*10^5 Дж s=800 м F=?===
A=F*s
F=A/s=2*10^5/800=250 H
========================