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TvoiOdnoklasnik16
@TvoiOdnoklasnik16
June 2022
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Под действием силы упругости 100 Н пружина растянулась на 0, 01м. Коэффициент жесткости пружины равен ... (?) Помогите пожалуйста
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fatt52
Verified answer
F=100 H x=0.01 м k=?
===
F=k*x
k=F/x=100/0.01=10000 Н/м (10^4 Н/м)
===================
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Answers & Comments
Verified answer
F=100 H x=0.01 м k=?===
F=k*x
k=F/x=100/0.01=10000 Н/м (10^4 Н/м)
===================