Подайте уравнение нейтрализации с использованием ионной записи
..... KOH + .... HCI ----> ............................ ............
..... Al (OH) 3 + .... H2SO4 ------> ............... ...........................
..... Zn (OH) 2 + .... HNO3 ------- > ..........................................
..... NaOH +. ... H2SO4 ------> ....................................... ...
..... KOH + .... HCI ----> ............................ ............
..... Al (OH) 3 + .... H2SO4 ------> ............... ...........................
..... Zn (OH) 2 + .... HNO3 ------- > ..........................................
..... NaOH +. ... H2SO4 ------> ....................................... ...
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Verified answer
KOH + HCl = KCl + H₂OK⁺+OH⁻+H⁺+Cl⁻ = K⁺+Cl⁻+H₂O
H⁺+OH⁻=H₂O
2Al(OH)₃ + 3H₂SO₄ = Al₂(SO₄)₃ + 6H₂O
2Al(OH)₃ + 6H⁺+3SO₄²⁻ = 2Al³⁺+3SO₄²⁻+6H₂O
2Al(OH)₃ + 6H⁺ = 2Al³⁺+6H₂O
Al(OH)₃ + 3H⁺ = Al³⁺+3H₂O
Zn(OH)₂+2HNO₃ = Zn(NO₃)₂ + 2H₂O
Zn(OH)₂ + 2H⁺+2NO₃⁻ = Zn²⁺+2NO₃⁻+2H₂O
Zn(OH)₂ + 2H⁺ = Zn²⁺+2H₂O
2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O
2Na⁺+2OH⁻+2H⁺+SO₄²⁻ = 2Na⁺+SO₄²⁻ + 2H₂O
2H⁺+2OH⁻ = 2H₂O
H⁺+OH⁻=H₂O