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Maarin
@Maarin
August 2022
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AnonimusPro
Verified answer
Sqrt(2x^2-3x+1)=sqrt(x^2-3x+2)
возводим обе части в квадрат, но:
2x^2-3x+1>=0 и x^2-3x+2>=0
2x^2-3x+1=x^2-3x+2
x^2-1=0
x^2=1
x1=1
x2=-1
проверяем:
2-3+1>=0 - верно
1-3+2>=0 - верно
2+3+1>=0 - верно
1+3+2>=0 - верно
Ответ: x1=1; x2=-1
2 votes
Thanks 1
miron2077
Verified answer
!!!!!!!!!!!!!!!!!!!!!!!
1 votes
Thanks 1
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Answers & Comments
Verified answer
Sqrt(2x^2-3x+1)=sqrt(x^2-3x+2)возводим обе части в квадрат, но:
2x^2-3x+1>=0 и x^2-3x+2>=0
2x^2-3x+1=x^2-3x+2
x^2-1=0
x^2=1
x1=1
x2=-1
проверяем:
2-3+1>=0 - верно
1-3+2>=0 - верно
2+3+1>=0 - верно
1+3+2>=0 - верно
Ответ: x1=1; x2=-1
Verified answer
!!!!!!!!!!!!!!!!!!!!!!!