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matochecaterina
@matochecaterina
July 2022
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подскажите, пожалуйста, как решить: log2 3=a, log8 18=?
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uekmyfhfp
Log8_18 = 1/3 * log2_18 = 1/3(log2_2 + log2_9) =
= 1/3* (1+ 2*log2_3) = 1/3 * (1+2*a) = (1+2a) / 3.
второй способ
log8_18 = (log2_18) / (log2_8)= (log2_2 + log2_9) / 3 = ( 1 + 2*log2_3) / 3 = =(1+2a)/3
2 votes
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Answers & Comments
= 1/3* (1+ 2*log2_3) = 1/3 * (1+2*a) = (1+2a) / 3.
второй способ
log8_18 = (log2_18) / (log2_8)= (log2_2 + log2_9) / 3 = ( 1 + 2*log2_3) / 3 = =(1+2a)/3