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prostttt
@prostttt
October 2021
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Полное решение! Спасибо заранее
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tolya91
7)
(28a/(16a²-b²))-(7/(4a+b))=(28a/((4a-b)(4a+b)))-(7/(4a+b))=(28a-7(4a-b))/((4a-b)(4a+b))=(7b)/((4a-b)(4a+b))=42/((8-6)·14)=42/28=1,5
8)-3(2+2x)-3x≤2
-6-6x-3x-2≤0
9x+8≥0
x≥-8/9
ответ 3
1 votes
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Answers & Comments
(28a/(16a²-b²))-(7/(4a+b))=(28a/((4a-b)(4a+b)))-(7/(4a+b))=(28a-7(4a-b))/((4a-b)(4a+b))=(7b)/((4a-b)(4a+b))=42/((8-6)·14)=42/28=1,5
8)-3(2+2x)-3x≤2
-6-6x-3x-2≤0
9x+8≥0
x≥-8/9
ответ 3