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prostttt
@prostttt
October 2021
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16
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Полное решение,спасибо
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kirichekov
Verified answer
1. ΔOHB:
OB=10, HO=6
по теореме Пифагора: 10²=6²+НВ², НВ=8, АВ=16
2. ΔОНВ: ОВ=10, ОН=9
по теореме Пифагора: 10²=9²+НВ². НВ=√19, АВ=2√19
уменьшилась на 16-2√19
1 votes
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Answers & Comments
Verified answer
1. ΔOHB:OB=10, HO=6
по теореме Пифагора: 10²=6²+НВ², НВ=8, АВ=16
2. ΔОНВ: ОВ=10, ОН=9
по теореме Пифагора: 10²=9²+НВ². НВ=√19, АВ=2√19
уменьшилась на 16-2√19