помагите пажалуста очень срочно. Created by ffxf. algebra-ru

помагите пажалуста очень срочно...

NNNLLL54

Verified answer

$5.41.\; \; 1)\; \; x^2-9=0\; ,\; \; x^2=9\; ,\; \; x_{1,2}=\pm 3\\\\2)\; \; x^2-0,04=0\; ,\; \; (x-0,2)(x+0,2)=0\; ,\; \; x=\pm 0,2\\\\3)\; \; x^2-81=0\; ,\; \; (x-9)(x+9)=0\; ,\; \; x_{1,2}=\pm 9\\\\4)\; \; y^2- \frac{1}{9}=0\; ,\; \; y^2= \frac{1}{3}\; ,\; \; y_{1,2}=\pm \frac{1}{3}\\\\5)\; \; y^2-1\frac{9}{16}=0\; ,\; \; y^2=\frac{25}{16}\; ,\; \; y_{1,2}=\pm \frac{5}{4}=\pm 1,25\\\\6)\; \; y^2-2\frac{1}{4}=0\; ,\; \; y^2=\frac{9}{4}\; ,\; \; x_{1,2}=\pm \frac{3}{2}=\pm 1,5$

$5.42.\; \; 1)\; \; 15,2\cdot 14,8=(15+0,2)(15-0,2)=15^2-(0,2)^2=\\\\=225-0,04=224,96\\\\2)\; \; 4,01\cdot 3,99=(4+0,01)(4-0,01)=4^2-(0,01)^2=\\\\=16-0,0001=15,9999\\\\3)\; \; 86^2-14^2=(86-14)(86+14)=72\cdot 100=7200\\\\4)\; \; (2\frac{3}{4})^2-(1\frac{1}{4})^2=(\frac{11}{4})^2-(\frac{5}{4})^2=(\frac{11}{4}-\frac{5}{4})(\frac{11}{4}+\frac{5}{4})=\\\\= \frac{6}{4}\cdot \frac{16}{4}= \frac{3}{2}\cdot 4=3\cdot 2=6$

0 votes Thanks 1

sedinalana 5.41
1)x²=9 x=-3 U x=3
2)x²=0,04 x=-0,2 U x=0,2
3)x²=81 x=-9 U x=9
4)y²=1/9 y=-1/3 u y=1/3
5)y=25/16 y=-5/4 U y=5/4
6)y²=9/4 y=-3/2u y=3/2
5.42
1)(15+0,1)(15-0,1)=225-0,01=224,99
3)(4+0,01)(4-0,01)=16-0,0001=15,9999
5)(86+14)(86-14)=100*72=7200
7)2 3/4+1 1/4)(2 3/4-1 1/4)=4*1 2/4=4*1+4*2/4=4+2=6

0 votes Thanks 1

Answers & Comments

Verified answer

pomagite pozhalksto srochno

pomogite ochen srochno169f67e4d11b56280b182c7045782e17 80914

pozhalusta prmagite srochno

ochen srochno nuzhno 163

pomagite pozhalustas 1 taskom

srochno nuzhno pomogite 476a 476g

pomogite nuzhno ochen srochno 462a

pomagite plizzzzzzzzzz

рекомендуемые вопросы

Helpful Links

Helpful Social