Home
О нас
Products
Services
Регистрация
Войти
Поиск
Ииррр1111
@Ииррр1111
December 2021
1
4
Report
Помагите решить пожалуйста
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
ShirokovP
Verified answer
1) (x^2 - 1)(x^2 + 3) = (x^2 + 1)^2 + x
x^4 + 3x^2 - x^2 - 3 = x^4 + 2x^2 + 1 + x
x^4 + 2x^2 - 3 = x^4 + 2x^2 + x + 1
x^4
+
2x^2
- 3 -
x^4
-
2x^2
- x - 1 = 0
- x - 4 = 0
- x = 4
x = - 4
Ответ
- 4
2) 4y^3 - 25y = 0
y (4y^2 - 25) = 0
y (2y - 5)(2y + 5) = 0
y = 0 ;
2y - 5 = 0 ==> y = 2,5
2y + 5 = 0 ==> y = - 2,5
Ответ
- 2,5 ; 0 ; 2,5
3) (6x - 1)^2 - (3x - 5)^2 = 0
(6x - 1 - 3x + 5)(6x - 1 + 3x - 5) = 0
(3x + 4)(9x - 6) = 0
3x + 4 = 0
3x = - 4
x = - 4/3;
9x - 6 = 0
9x = 6
x = 2/3
Ответ
- 4/3; 2/3
2 votes
Thanks 0
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Помагите решить пожалуйста..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1) (x^2 - 1)(x^2 + 3) = (x^2 + 1)^2 + xx^4 + 3x^2 - x^2 - 3 = x^4 + 2x^2 + 1 + x
x^4 + 2x^2 - 3 = x^4 + 2x^2 + x + 1
x^4 + 2x^2 - 3 - x^4 - 2x^2 - x - 1 = 0
- x - 4 = 0
- x = 4
x = - 4
Ответ
- 4
2) 4y^3 - 25y = 0
y (4y^2 - 25) = 0
y (2y - 5)(2y + 5) = 0
y = 0 ;
2y - 5 = 0 ==> y = 2,5
2y + 5 = 0 ==> y = - 2,5
Ответ
- 2,5 ; 0 ; 2,5
3) (6x - 1)^2 - (3x - 5)^2 = 0
(6x - 1 - 3x + 5)(6x - 1 + 3x - 5) = 0
(3x + 4)(9x - 6) = 0
3x + 4 = 0
3x = - 4
x = - 4/3;
9x - 6 = 0
9x = 6
x = 2/3
Ответ
- 4/3; 2/3