Ответ:
3n²-3m²/n²+np : 6m-6n/n+p =
3(n²-m²)/n(n+p) × n+p/6(m-n)=
3(n-m)(n+m)/n(n+p) × n+p/6(m-n)=
3(n-m)(n+m)/n(n+p) × - (n+p)/6(n-m)= (n+m)/n × - 1/2= (-3-9)/
(-3) × - 1/2=-12/(-3) × -1/2=-2
Объяснение:
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Ответ:
3n²-3m²/n²+np : 6m-6n/n+p =
3(n²-m²)/n(n+p) × n+p/6(m-n)=
3(n-m)(n+m)/n(n+p) × n+p/6(m-n)=
3(n-m)(n+m)/n(n+p) × - (n+p)/6(n-m)= (n+m)/n × - 1/2= (-3-9)/
(-3) × - 1/2=-12/(-3) × -1/2=-2
Объяснение: