Помогаем) щедро отблагодарю вновь)Срочно!!!!. Created by блондинка111. algebra-ru

Помогаем) щедро отблагодарю вновь)Срочно!!!!...

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$\frac{1}{3}^{4-3x}=3^3\\
3^{3x-4}=3^3\\
3x-4=3\\
3x=7\\
 x=\frac{7}{3}\\
\\
(2*\sqrt[3]{4})^x=8\\
2^{\frac{2x}{3}+x}=2^3\\
\frac{5x}{3}=3\\
5x=9\\
x=\frac{9}{5}
\\
17^x*17^{5+x}=17\\
17^{2x+5}=17\\
2x+5=1\\
2x=-4\\
x=-2\\
\\
(\frac{2}{5})^x=(\frac{4}{9})^{\frac{x}{2}}\\
\frac{2}{5}^x=\frac{2}{3}^x\\
\frac{3}{5}^x=1\\
x=log_{\frac{3}{5}}1\\
x=0\\
\\
4^{x-3}+4^x=65\\
\frac{4^x}{64}+4^x=65\\
4^x+64*4^x=65*64\\
65*4^x=65*64\\
4^x=64\\
x=3\\
\\
3^{\sqrt{(x+1)^2}}=3\\
x+1=1\\
x=0
$

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mmb1

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1/ (1/3)^(4-3x)=27
(3)^-(4-3x)=3^3
-4+3x=3
x=7/3
2/ $(2 \sqrt[2]{4} )^x=8$
$( \sqrt[3]{2^2*2^3} )^x=2^3$
$(2^{5/3})^x=2^3$
5/3x=3
x=9/5
3/ 17^x*17^(5+x)=17^1
x+5+x=1
2x=-4
x=-2
4/ (2/5)^x=(4/9)^x/2
(2/5)^x=(2/3)^x
x lg 2/5= x lg 2/3
x=0
5/ 4^(x-3)+4^x=65
4^(x-3)(1+4^3)=65
4^(x-3)*65=65
4^(x-3)=1
x-3=0
x=3
6/ $3^{ \sqrt{(x+1)^2} } =3^1$
$\sqrt{(x+1)^2}=1$
!x+1!=1
x=0
x=-2

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