ODЗ:  х>0              1+x>0      x>-1

x≤1/8                          4-x²>0      (2-x)(2+x)>0      

х∈(0;1/8]                      2-x>0    -x>-2       X<2

                                       2+X>0     X>-2

                                         X∈(-2;2)