5/x + 10/x(x-2) = (1+x)/(x-2)
ОДЗ: x≠0, x≠2
5(x-2)+10=(1+x)*x
5x-10+10-x-x²=0
4x-x²=0
x(4-x)=0
x1= 0 - не корень x2= 4
x=4
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Verified answer
5/x + 10/x(x-2) = (1+x)/(x-2)
ОДЗ: x≠0, x≠2
5(x-2)+10=(1+x)*x
5x-10+10-x-x²=0
4x-x²=0
x(4-x)=0
x1= 0 - не корень x2= 4
x=4