Помогииииите √2 sin x+1=0. Created by nastyavetka15. algebra-ru

Помогииииите √2 sin x+1=0...

sedinalana $\sqrt{2}*sinx+1=0
\\\sqrt{2}sinx=-1
\\sinx= -\frac{1}{\sqrt{2}} 
\\sinx=- \frac{\sqrt{2}}{2} 
\\x=(-1)^{n+1} \frac{\pi}{4} +\pi n$
Ответ: $x=(-1)^{n+1} \frac{\pi}{4} +\pi n$

2 votes Thanks 1

AnonimusPro

Verified answer

√2sinx+1=0
√2sinx=-1
sinx=-1/√2
x=(-1)^(k+1)*π/4+πk,k∈z

3 votes Thanks 1

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