ПОМОГИОЕ С АЛГЕБРОЙ!!!!!. Created by 1234282773646. algebra-ru

ПОМОГИОЕ С АЛГЕБРОЙ!!!!!...

Ответ:

$\sqrt{36}=\sqrt{6^2}=6\ \ ,\ \ \ \sqrt{64}=\sqrt{8^2}=8\ \ \ ,\ \ \ \sqrt{144}=\sqrt{12^2}=12\\\\\\\sqrt{0,04}=\sqrt{0,2^2}=0,2\ \ ,\ \ \ \sqrt{0,49}=\sqrt{0,7^2}=0,7\ \ ,\ \ \sqrt{1,69}=\sqrt{1,3^2}=1,3$

$\sqrt{2500}=\sqrt{50^2}=50\ \ ,\ \ \ \sqrt{10\, 000}=\sqrt{100^2}=100\ \ ,\\\\\\\sqrt{\dfrac{16}{121}}=\sqrt{\dfrac{4^2}{11^2}}=\dfrac{4}{11}\ \ ,\ \ \sqrt{5\dfrac{4}{9}}=\sqrt{\dfrac{49}{9}}=\sqrt{\dfrac{7^2}{3^2}}=\dfrac{7}{3}\ \ ,\\\\\\\sqrt{0,0009}=\sqrt{(0,03)^2}=0,03\ \ ,\ \ \ \sqrt{0,0196}=\sqrt{(0,14)^2}=0,14$

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Verified answer

Ответ:

1) 6

2)8

3)12

4)0,2

5)0,7

6)1,3

7)50

8)100

9)0,36

10) 7/3

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