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ALMIRA7779
@ALMIRA7779
July 2022
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Помогите 1243 3 и 4
Выразите переменную х через переменную у из линейного уравнения
5х+11у-3=0
-7х+6у-1=0
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zhenyaM2002
Verified answer
5х + 11у - 3 = 0
5х = 3 - 11у
х = (3-11у) / 5
х = 1/5 * (3-11у)
х= 0,2 * (3-11у)
х= 0,6 - 2,2у
-7х + 6у - 1 = 0
-7х = 1 - 6у
х = (1 - 6у) / (-7)
х = - (1-6у)/7
х= - 1/7 * (1 - 6у)
х =
x =
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Answers & Comments
Verified answer
5х + 11у - 3 = 05х = 3 - 11у
х = (3-11у) / 5
х = 1/5 * (3-11у)
х= 0,2 * (3-11у)
х= 0,6 - 2,2у
-7х + 6у - 1 = 0
-7х = 1 - 6у
х = (1 - 6у) / (-7)
х = - (1-6у)/7
х= - 1/7 * (1 - 6у)
х =
x =