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polkanyasha
@polkanyasha
August 2022
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Помогите 1,5,6, очень буду благодарна
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Dимасuk
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1. (2x + 1)² - 4(x - 3)(3 + x) = 4x² + 4x + 1 - 4(x² - 9) = 4x² + 4x + 1 - 4x² + 36 = 4x + 37 (нужно воспользоваться формулами разности квадрата и квадратом суммы).
5. 13 2/5 - 11,2: 9 1/3 = 13,4 - 11,2:28/3 = 13,4 - 11,2·3/28 = 13,4 - 0,4·3 =
13,4 - 1,2 = 12,2
6. (-1/3a²b)³ - (-9a³b²)² = -a⁶b³/27 - 81a⁶b⁴
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Answers & Comments
Verified answer
1. (2x + 1)² - 4(x - 3)(3 + x) = 4x² + 4x + 1 - 4(x² - 9) = 4x² + 4x + 1 - 4x² + 36 = 4x + 37 (нужно воспользоваться формулами разности квадрата и квадратом суммы).5. 13 2/5 - 11,2: 9 1/3 = 13,4 - 11,2:28/3 = 13,4 - 11,2·3/28 = 13,4 - 0,4·3 =
13,4 - 1,2 = 12,2
6. (-1/3a²b)³ - (-9a³b²)² = -a⁶b³/27 - 81a⁶b⁴