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01NoName10
@01NoName10
July 2022
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Помогите 2 примера решить плс
а(2b+1)-b(2a-1) при a=10, b= -5
4а"(5а-3b)-5a"(4a+b) при а= -2 , b= -3
" это в квадрате - 2 степень
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isaevaliza09
10×(2×(-5)+1)+5×(2×10-1)=5
4×(-2)"×(5×(-2)-3×(-3))-5×(-2)"×(4×(-2)+(-3))=204
2 votes
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Answers & Comments
4×(-2)"×(5×(-2)-3×(-3))-5×(-2)"×(4×(-2)+(-3))=204