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kbibeeva
@kbibeeva
June 2022
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Помогите
2sin^2 2x-3sin2x+1=o
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sedinalana
2sin^2 2x-3sin2x+1=o
sin2x=a
2a
²-3a+1=0
D=9-8=1
a1=(3-1)/4=1/2⇒sin2x=1/2
2x=π/6+2πk U 2x=5π/6+2πk
x=π/12+πk U x=5π/12+πk,k∈z
a2=(3+1)/4=1⇒sin2x=1
2x=π/2+2πk⇒x=π/4+πk,k∈z
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Answers & Comments
sin2x=a
2a²-3a+1=0
D=9-8=1
a1=(3-1)/4=1/2⇒sin2x=1/2
2x=π/6+2πk U 2x=5π/6+2πk
x=π/12+πk U x=5π/12+πk,k∈z
a2=(3+1)/4=1⇒sin2x=1
2x=π/2+2πk⇒x=π/4+πk,k∈z