Home
О нас
Products
Services
Регистрация
Войти
Поиск
НикольV
@НикольV
August 2022
1
0
Report
помогите. алгебра 10 класс. 1 столбик
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
verakutuzova20
1)log(2)8=x 2)log(1/2)1/16=x 3)log(1/2)8=x 4)log(10)∛10=x 5)log(81)9=x
2^x=8 1/2^x=1/16 (1/2)^x=8 10^x=10^1/3 81^x=9
2^x=2^3 1/2^x=(1/2)^4 (1/2)^x=(1/2)^-3 x=1/3 (9^2)^x=9
x=3 x=4 x=-3 2x=1
x=1/2
6)log(4√3)9=x 7)36^log(6)5=6^2log(6)5
4√3^x=9
(3^1/4)^x=3^2
1/4^x=2
x=1/2
9)log(1/2)9-log(1/2)36=Log(1/2)9/36=log(1/2)1/4=2
1 votes
Thanks 0
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "помогите. алгебра 10 класс. 1 столбик..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2^x=8 1/2^x=1/16 (1/2)^x=8 10^x=10^1/3 81^x=9
2^x=2^3 1/2^x=(1/2)^4 (1/2)^x=(1/2)^-3 x=1/3 (9^2)^x=9
x=3 x=4 x=-3 2x=1
x=1/2
6)log(4√3)9=x 7)36^log(6)5=6^2log(6)5
4√3^x=9
(3^1/4)^x=3^2
1/4^x=2
x=1/2
9)log(1/2)9-log(1/2)36=Log(1/2)9/36=log(1/2)1/4=2