Ответ:
Объяснение:
2cos x ≤ √3
cos x ≤ √3/2
cos x = √3/2
x1 π/6 + 2πn, n∈Z
х2= -π/6 + 2πn, n∈Z
ответ: (-∞; -π/6] ∪ [π/6; +∞)
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Ответ:
Объяснение:
2cos x ≤ √3
cos x ≤ √3/2
cos x = √3/2
x1 π/6 + 2πn, n∈Z
х2= -π/6 + 2πn, n∈Z
ответ: (-∞; -π/6] ∪ [π/6; +∞)