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ТОРТилла2
@ТОРТилла2
March 2022
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Помогите, братишки по химии
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AIhimik
Дано:
Vр-ра(KOH) = 120 см3
рр-ра(KOH) = 1,109 г/см3
w(KOH) = 12 %
Найти:
m(CH3-COOK) - ? (г)
Решение:
CH3-COOH + KOH ---> CH3-COOK + H2O
mp-pa(KOH) = 120 x 1,109 = 133,08 г
m(KOH) = (133,08 x 12)/100 = 16 г
n(KOH) = 16/56 = 0,3 моль
n(CH3-COOK) =
0,3 моль
m(
CH3-COOK) = 0,3 x 98 = 29,4 г
Ответ:
m(CH3-COOK
) = 29,4 г
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Answers & Comments
Vр-ра(KOH) = 120 см3
рр-ра(KOH) = 1,109 г/см3
w(KOH) = 12 %
Найти:
m(CH3-COOK) - ? (г)
Решение:
CH3-COOH + KOH ---> CH3-COOK + H2O
mp-pa(KOH) = 120 x 1,109 = 133,08 г
m(KOH) = (133,08 x 12)/100 = 16 г
n(KOH) = 16/56 = 0,3 моль
n(CH3-COOK) = 0,3 моль
m(CH3-COOK) = 0,3 x 98 = 29,4 г
Ответ: m(CH3-COOK) = 29,4 г