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11ALeN11
@11ALeN11
November 2021
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ПОМОГИТЕ, ЧЕМ СМОЖЕТЕ!!! ПЕРВООБРАЗНАЯ
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sedinalana
Verified answer
3
а) f(x) = sinx - cosx , F(П)=1
F(x)=-cosx-sinx+C
1=-cosπ-sinπ+C
1=1-0+C
C=0
F(x)=-cosx-sinx
б) f(x) = x^2/3 - 3/x^2, F(3)=5
F(x)=x∛x²+3/x+C
5=3∛9+1+C
C=4-∛9
F(x)=x∛x²+3/x+4-∛9
в)F(x)=x²-5x+C
-2=1-5+C
c=2
F(x)=x²-5x+2
г)F(x)=2√(x-2)+C
10=2*2+C
C=6
F(x)=2√(x-2)+6
2
а)F(x)=-1/3*cos3x-4tg(x/2)+C
б)F(x)=1//x³-√x+C
в)
f(x)=-(4-5x)^4/20+1/[4(2x-1)²]+C
г)f(x)=x²/2-5sin2x+C
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Answers & Comments
Verified answer
3а) f(x) = sinx - cosx , F(П)=1
F(x)=-cosx-sinx+C
1=-cosπ-sinπ+C
1=1-0+C
C=0
F(x)=-cosx-sinx
б) f(x) = x^2/3 - 3/x^2, F(3)=5
F(x)=x∛x²+3/x+C
5=3∛9+1+C
C=4-∛9
F(x)=x∛x²+3/x+4-∛9
в)F(x)=x²-5x+C
-2=1-5+C
c=2
F(x)=x²-5x+2
г)F(x)=2√(x-2)+C
10=2*2+C
C=6
F(x)=2√(x-2)+6
2
а)F(x)=-1/3*cos3x-4tg(x/2)+C
б)F(x)=1//x³-√x+C
в)
f(x)=-(4-5x)^4/20+1/[4(2x-1)²]+C
г)f(x)=x²/2-5sin2x+C