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Da7296
@Da7296
July 2022
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ПОМОГИТЕ!!! Дан треугольник АВС. Найдите величину угла А, если ВС = 11√3, АС=11√2, а угол В = 45°
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anmih
Verified answer
По теореме синусов:
ВС / sin A = AC / sin B
11√3 / sin A = 11√2 / sin 45
11√3 / sin A = 11√2 / √2/2
sin A = √3/2
уг А = 60*
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Verified answer
По теореме синусов:ВС / sin A = AC / sin B
11√3 / sin A = 11√2 / sin 45
11√3 / sin A = 11√2 / √2/2
sin A = √3/2
уг А = 60*