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elgrey
@elgrey
July 2022
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армения20171
(sina+cosa)/√2=cos(a-π/4)
cos(a-π/4)=cosacosπ/4+sinasinπ/4=
1/√2*cosa+1/√2*sina=(sina+cosa)/√2
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elgrey
Можете ещё это доказать :
2/sin2a+1=1+ tg^2(a-pi/4)
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Answers & Comments
cos(a-π/4)=cosacosπ/4+sinasinπ/4=
1/√2*cosa+1/√2*sina=(sina+cosa)/√2
2/sin2a+1=1+ tg^2(a-pi/4)