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masha489
@masha489
June 2022
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sangers1959
Verified answer
(1-cosα+cos(2α)/(sin(2α)-sinα)=
=(sin²α+cos²α-cosα+cos²α-sin²α)/(2sinα*cosα-sinα)=
=(2*cos²α-cosα)/(sinα*(2cosα-1)=
=(cosα*(2cosα-1)/(sinα*(2cosα-1)=cosα/sinα≡ctgα.
1 votes
Thanks 1
masha489
спасибо большое!!
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Answers & Comments
Verified answer
(1-cosα+cos(2α)/(sin(2α)-sinα)==(sin²α+cos²α-cosα+cos²α-sin²α)/(2sinα*cosα-sinα)=
=(2*cos²α-cosα)/(sinα*(2cosα-1)=
=(cosα*(2cosα-1)/(sinα*(2cosα-1)=cosα/sinα≡ctgα.