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1HeDgEhOg1
@1HeDgEhOg1
July 2022
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Помогите! Хотя бы одно! ВОПРОС ЖИЗНИ И СМЕРТИ!
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sangers1959
Verified answer
Пусть а⁻⁵=t ⇒
Выражение принимает следующий вид:
((t/(t-6)-2t/(t²-12t+36))*((36-t²)/(t-8))+12t/(t-6).
1. 2t/(t²-12t+36)=2t/(t-6)².
2. t/(t-6)-2t/(t-6)²=(t*(t-6)-2t)/(t-6)²=(t²-6t-2t)/(t-6)²=(t²-8t)/(t-6)²=t*(t-8)/(t-6)².
3. (36-t²)/(t-8)=(6-t)(6+t)/(t-8)=-(t-6)(t+6)/(t-8).
4. t*(t-8)*(-(t-6)(t+6)/((t-6)²*(t-8))=-t*(t+6)/(t-6)=(-t²-6t)/(t-6).
5. (-t²-6t)/(t-6)+12t/(t-6)=(-t²-6t+12t)/(t-6)=(-t²+6t)/(t-6)=-t*(t-6)/(t-6)=-t=-a⁻⁵.
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Thanks 1
1HeDgEhOg1
А второе, можно?)
sangers1959
7x√(49x³y⁵)+3x²y√(64y³)-5√(36x⁵y⁵)=7x*7xy²*√(xy)+3x²y*8y*√y-5*6x²y²*√(xy)=
=49x²y²*√(xy)+24x²y²*√y-30x²y²*√(xy)=19x²y²*√(xy)+24x²y²*√y=
=x²y²√y(19√x+24).
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Answers & Comments
Verified answer
Пусть а⁻⁵=t ⇒Выражение принимает следующий вид:
((t/(t-6)-2t/(t²-12t+36))*((36-t²)/(t-8))+12t/(t-6).
1. 2t/(t²-12t+36)=2t/(t-6)².
2. t/(t-6)-2t/(t-6)²=(t*(t-6)-2t)/(t-6)²=(t²-6t-2t)/(t-6)²=(t²-8t)/(t-6)²=t*(t-8)/(t-6)².
3. (36-t²)/(t-8)=(6-t)(6+t)/(t-8)=-(t-6)(t+6)/(t-8).
4. t*(t-8)*(-(t-6)(t+6)/((t-6)²*(t-8))=-t*(t+6)/(t-6)=(-t²-6t)/(t-6).
5. (-t²-6t)/(t-6)+12t/(t-6)=(-t²-6t+12t)/(t-6)=(-t²+6t)/(t-6)=-t*(t-6)/(t-6)=-t=-a⁻⁵.
=49x²y²*√(xy)+24x²y²*√y-30x²y²*√(xy)=19x²y²*√(xy)+24x²y²*√y=
=x²y²√y(19√x+24).