a)(x-12)(3x+9)=0
3x²+9x-36х-108=0
3x²-27x-108=0
D=729+1296=2025
√D=45
x1,2=-9±45//6
x1=-9+45//6=36//6=6
x2=-9-45//6=-54//6=-9
в)x²+7x=0
x*(x+7)=0
x1=0 x+7=0
x2=-7
г)x²-25=0
x=±√25
x1=5 x2=-5
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Answers & Comments
a)(x-12)(3x+9)=0
3x²+9x-36х-108=0
3x²-27x-108=0
D=729+1296=2025
√D=45
x1,2=-9±45//6
x1=-9+45//6=36//6=6
x2=-9-45//6=-54//6=-9
в)x²+7x=0
x*(x+7)=0
x1=0 x+7=0
x2=-7
г)x²-25=0
x=±√25
x1=5 x2=-5