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max1167
@max1167
August 2022
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Помогите, надо срочно, только букву А
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hlopushinairina
1.152 (b²+8b+16)/b ·(b/(b+4)²+b/(16-b²))+8/(b-4)=
=(b+4)²/b ·[(b(4-b)+b(b+4))/(b+4)(16-b²)]+8/(b-4)=
=(b+4)²/b·(4b-b²+b²+4b)/(b+4)(16-b²)+8/(b-4)=[(b+4)²/b·(8b/(b+4)(16-b²)]+8/(b-4)=
=(b+4)²·8b/(b(b+4)(16-b²) +8/(b-4)=8/(4-b)+8/(b-4)=8/(4-b)-8/(4-b)=0;
1.153 y/(y+2)+[1/(4-y²)-1/(4-4y+y²)]:2/(y-2)²=
=y/(y+2)+[1/(4-y²)-1/(y-2)²]:2/(y-2)²=y/(y+2)+[-(y-2)-(y+2)]·(y-2)²/[2(y-2)²(y+2)]=
=y/(y+2)+(-y+2-y-2)·(y-2)²/2(y-2)²(y+2)=y/(y+2)+(-2y·(y-2)²/2(y-2)²(y+2)=
=y/(y+2)-y/(y+2)=0
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Answers & Comments
=(b+4)²/b ·[(b(4-b)+b(b+4))/(b+4)(16-b²)]+8/(b-4)=
=(b+4)²/b·(4b-b²+b²+4b)/(b+4)(16-b²)+8/(b-4)=[(b+4)²/b·(8b/(b+4)(16-b²)]+8/(b-4)=
=(b+4)²·8b/(b(b+4)(16-b²) +8/(b-4)=8/(4-b)+8/(b-4)=8/(4-b)-8/(4-b)=0;
1.153 y/(y+2)+[1/(4-y²)-1/(4-4y+y²)]:2/(y-2)²=
=y/(y+2)+[1/(4-y²)-1/(y-2)²]:2/(y-2)²=y/(y+2)+[-(y-2)-(y+2)]·(y-2)²/[2(y-2)²(y+2)]=
=y/(y+2)+(-y+2-y-2)·(y-2)²/2(y-2)²(y+2)=y/(y+2)+(-2y·(y-2)²/2(y-2)²(y+2)=
=y/(y+2)-y/(y+2)=0