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Найдите сумму целых корней уравнения:
(x^+11x+28)*(6x-12)=0
Найдите сумму целых корней уравнения:
(x^+11x+28)*(6x-12)=0
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D = 121 - 112 = 9 = 3^2
x1 = (-11 + 3)/2 = -4
x2 = (-11-3)/2 = -7
6x-12 = 0
x3 = 2
x1 + x2 + x3 = -4 -7 + 2 = -9