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lesik2002hl
@lesik2002hl
July 2022
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помогите найти корень уравнения, 7y-1\12-y+1\4=2y+5\3
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2004Z
7y-1/12 - y+1/4 =2y+5/3
НОК (12,4,2)=12
(7y-1)*12 -(y+1)*12 = (2y+5) *12
____ ___ _____
12 4 3
7y-1-3y+1=4(2y+5)
7y-1-3y+1=8y+20
7y-3y-8y=1-1+20
7y-3y-8y=20+4
-4y=24
y=24:(-4)
y=-6
5 votes
Thanks 9
zarina910
7y-1-3y+1=4(2y+5)
7y-1-3y+1=8y+20
7y-3y-8y=1-1+20
7y-3y-8y=20+4
-4y=24
y=24:(-4)
y=-6
4 votes
Thanks 2
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Answers & Comments
НОК (12,4,2)=12
(7y-1)*12 -(y+1)*12 = (2y+5) *12
____ ___ _____
12 4 3
7y-1-3y+1=4(2y+5)
7y-1-3y+1=8y+20
7y-3y-8y=1-1+20
7y-3y-8y=20+4
-4y=24
y=24:(-4)
y=-6
7y-1-3y+1=8y+20
7y-3y-8y=1-1+20
7y-3y-8y=20+4
-4y=24
y=24:(-4)
y=-6