2^x + 2^y = 2^xy = 2^x * 2^y
2^y = (2^x + 2^y) / 2^x
y = log2 (2^x + 2^y) / 2^x
y' = (log2 (2^x + 2^y) / 2^x)' = 1 / ( (2^x + 2^y) / 2^x) * ln 2
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2^x + 2^y = 2^xy = 2^x * 2^y
2^y = (2^x + 2^y) / 2^x
y = log2 (2^x + 2^y) / 2^x
y' = (log2 (2^x + 2^y) / 2^x)' = 1 / ( (2^x + 2^y) / 2^x) * ln 2