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sofia9915
@sofia9915
August 2022
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Помогите найти производную функции. Срочно
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sedinalana
1
y`=[((3x²+5)³)`*(2x-3)-(2x-3)`*(3x²+5)³]/(2x-1)²=
=[3(3x²+5)²*6x*(2x-1)-2(3x²+5)³]/(2x-1)²=2(3x²+5)(18x²-27x-3x²-5)/(2x-1)²=
=2(3x²+5)(15x²-27x-5)/(2x-1)²
2
y`=[tg²(x²+1)]`*[tg(x²+1)]`*(x²+1)`=2tg(x²+1)*1/cos(x²+1)*2x=8x*tg(x²+1)/cos²(x²+1)
3
y`=[(1+cos²x)^1/4]`*(1+cos²x)`=
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Answers & Comments
y`=[((3x²+5)³)`*(2x-3)-(2x-3)`*(3x²+5)³]/(2x-1)²=
=[3(3x²+5)²*6x*(2x-1)-2(3x²+5)³]/(2x-1)²=2(3x²+5)(18x²-27x-3x²-5)/(2x-1)²=
=2(3x²+5)(15x²-27x-5)/(2x-1)²
2
y`=[tg²(x²+1)]`*[tg(x²+1)]`*(x²+1)`=2tg(x²+1)*1/cos(x²+1)*2x=8x*tg(x²+1)/cos²(x²+1)
3
y`=[(1+cos²x)^1/4]`*(1+cos²x)`=