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ukflbfnjh147
@ukflbfnjh147
July 2022
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shevtsovavalia
1)f⁾(x)=4sin2xcos2x = 2sin4x
f(π/16)= 2sinπ/4 = 2*√2/2 = √2
2)f⁾(x) = -4sin2xcos2x = -2sin4x
f(π/16) = -2*√2/2 = -√2
3)f⁾(x) = 6tg3x*1/cos²3x
f⁾(π/12) = 6tgπ/4 *4/2 = 12
6) 2tgx*1/cos²x + 2ctg*1/sin²x
f⁾(π/4) = 2*1*4/2+2*1*4/2 = 4+4=8
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Answers & Comments
f(π/16)= 2sinπ/4 = 2*√2/2 = √2
2)f⁾(x) = -4sin2xcos2x = -2sin4x
f(π/16) = -2*√2/2 = -√2
3)f⁾(x) = 6tg3x*1/cos²3x
f⁾(π/12) = 6tgπ/4 *4/2 = 12
6) 2tgx*1/cos²x + 2ctg*1/sin²x
f⁾(π/4) = 2*1*4/2+2*1*4/2 = 4+4=8