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dianka991
@dianka991
July 2022
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Помогите написать полное и сокращенное ионное уравнение
1. Fe (OH) 3+ NaOH-->
2. Cu(OH) 2+H3PO4-->
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monkeyme
н р р н
1. Fe(OH)₃ + NaOH → NaFeO₂ + 2H₂O
Fe(OH)₃ +
Na⁺
+ OH⁻ →
Na⁺
+ FeO₂ + 2H₂O
Fe(OH)₃ + OH⁻ → FeO₂ + 2H₂O
н р р
2. 3Cu(OH)₂ + 2H₃PO₄ → Cu₃(PO₄)₂ + 6H₂O
3Cu(OH)₂ + 6H⁺ +
2PO₄³⁻
→ 3Cu²⁺ +
2PO₄³⁻
+ 6H₂O
3Cu(OH)₂ + 6H⁺ → 3Cu²⁺ + 6H₂O
Cu(OH)₂ + 2H⁺ → Cu²⁺ + 2H₂O
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Answers & Comments
1. Fe(OH)₃ + NaOH → NaFeO₂ + 2H₂O
Fe(OH)₃ + Na⁺ + OH⁻ → Na⁺ + FeO₂ + 2H₂O
Fe(OH)₃ + OH⁻ → FeO₂ + 2H₂O
н р р
2. 3Cu(OH)₂ + 2H₃PO₄ → Cu₃(PO₄)₂ + 6H₂O
3Cu(OH)₂ + 6H⁺ + 2PO₄³⁻ → 3Cu²⁺ + 2PO₄³⁻ + 6H₂O
3Cu(OH)₂ + 6H⁺ → 3Cu²⁺ + 6H₂O
Cu(OH)₂ + 2H⁺ → Cu²⁺ + 2H₂O