Ответ:

Пошаговое объяснение:

1) (a²+ab+c²+2ac+bc)/(a²-2bc-c²-b²)=((a²+2ac+c²)+(ab+bc))/(a²-(b²+2bc+c²))=((a+c)²+b(a+c))/(a²-(b+c)²)=((a+c)(a+b+c))/((a-b-c)(a+b+c))=(a+c)/(a-b-c)

2) (a²-c²-4ab+4b²)/(a²-4ab+ac+4b²-2bc)=((a²-4ab+4b²)-c²)/((a²-4ab+4b²)+(ac-2bc))=((a-2b)²-c²)/((a-2b)²+c(a-2b))=((a-2b-c)(a-2b+c))/((a-2b)(a-2b+c))=(a-2b-c)/(a-2b)

3) (y²-x²-25z²+10xz)/(2xy-5xz+x²-5yz+y²)=(y²-(x²-10xz+25z²))/((x²+2xy+y²)-(5xz+5yz))=(y²-(x-5z)²)/((x+y)²-5z(x+y))=((y-x+5z)(y+x-5z))/((x+y)(x+y-5z))=(-x+y+5z)/(x+y)=-(x-y-5z)/(x+y)

4) (x²+y²+6zx+2xy+6zx)/(y²-x²-12xz-36z²)=((x²+2xy+y²)+(6xz+6yz))/(y²-(x²+12xz+36z²))=((x+y)²+6z(x+y))/(y²-(x+6z)²)=((x+y)(x+y+6z))/((y-x-6z)(y+x+6z))=(x+y)/(-x+y-6z)=-(x+y)/(x-y+6z)